I will help for the calculation only, for discussion, explanation and reflection, please try to do yourself
All the best
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who walks on the ground.....
最近不懂搞什么,爱上写布落格,还用华语,不懂原因,只想写。。。。
还好,有个爱徒,Emily,她竟然帮我翻译,谢谢您,这一次再麻烦您。
谈到读书,对大部分的人来说,难过吃“粪”,也许你会说,咦,老师你很脏
对我来说,粪 = 读书,又爱又恨
一天不拉,总觉得不爽,身体不舒服,建康出问题。
一天不读,考试考不好,心里不舒服,成绩出问题。
长久不拉,身体藏毒素,口气臭,暗疮多,多病痛 ;拉了,粪又臭。
读书呢,一样的;想读,又难读;不读,又不行;读了,又不定有好成绩。
又爱又恨
读书难,正的很难。我自己也觉得难,每个月,我都买两本杂志,每个月我都读不完。为什么?这世界太美丽,太多好玩的,读到一半,想看电视,听音乐,上网,书就放一旁,一天拖一天,又到下个月,又有新杂志,又读不完了。。。!
我也做不到,我怎么要我的学生读呢?
有时,很想跟我学生说,“对不起”,我也不想逼你们,可是,粪是要拉,书是要读的。
不读不读也要读,那如何读呢?
最近,想到了办法,不要读书,听书….
F4
1b) i) Increases
ii) Because the gradient of the graph increases
c) i) Because the gravitational acceleration is 10 ms-2
ii) Reduces due to air resistance
2a) i) going up hill
ii) going down hill
b) i) 125 m (area under the graph from 10 to 20s )
ii) – 1 ms-2
3a) – 80 kg ms-1
b) No, because the total momentum in a closed system is constant
4a) i) 3
ii) weight, reaction force and string tension
b) string tension = 1000 N
reaction force = 866 N
5a) i) with and without air resistance
ii) air resistance is reducing the speed of motion
b) fall at the same time
6a) the product of mass and acceleration
b) F – f = ma
c) i) F3 = water resistance
ii) 466 N
iii) 2.33 ms-2
7 a) 4500 x 0.1 = 450 J
b) 25 x 2π x 0.15 x 40 = 942 J
c) 450 / 942 x 100 % = 47.7 %
d) 1. as heat energy
2. as sound energy
e) Yes because it reduce the mass of the screwjack
f) 1. Ligher platform
2. reducing frictional force
8 a) i) P
ii) highest spring constant
b) 1. Diameter of the spring
2. diameter of the wire
c) Can. It will help to withstand a higher load
d) Because the elastic limit of the spring is exceeded
e) k = F/x = 500 Nm-1
F5
1. D 2. C 3. A 4. B 5. D 6. D 7. C 8. C 9. C 10. B
11. B 12. D 13. B 14. B 15. A 16. D 17. D 18. D 19. D 20. A
1 a) Small surface area. Charges are accumulated at low surface area
b) n = Q/e = 6.25 x 1019
2 a) Ability of a conductor to resist current flow
b) voltmeter parallel to the bulb while the ammeter series to the bulb
c) the reading of the voltmeter divide with the reading of the ammeter
d) R = V/I = 10 Ω
3 a) i) 0.13 A
ii) 0.33 A
b) 22 Ω
c) i) 30 Ω
ii) 0.24 A
4a) i) It needs 240 V of input potential difference to generate 2000 W of output power
ii) I = P/ V = 8.33 A
iii) 9 A because the maximum current flow is 8.33 A